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^= operator in Bash is the bitwise Exclusive OR (XOR) assignment operator. It evaluates the right-hand operand, performs a bitwise XOR operation against the current integer value of the left-hand variable, and assigns the resulting integer back to that variable.
Because Bash does not natively support floating-point arithmetic, this operator functions strictly on integers within an arithmetic evaluation context.
Syntax
The operator must be executed inside an arithmetic context, such as the((...)) compound command, the $((...)) arithmetic expansion, or the let builtin.
let builtin:
Technical Mechanics
- Arithmetic Context Requirement: The
^=operator is not recognized in standard shell command execution. It is only parsed as an assignment operator when enclosed in arithmetic boundaries. - Evaluation Order: The expression on the right side of the operator is fully evaluated first. The bitwise XOR is then applied between the evaluated result and the left-hand variable.
- Bitwise Logic: The XOR operation compares the binary representations of the two integers bit by bit.
- If the bits at a given position are different (one is
0and the other is1), the resulting bit is1. - If the bits are identical (both
0or both1), the resulting bit is0.
- If the bits at a given position are different (one is
- Implicit Initialization: If the target variable is unset or contains a null string, Bash implicitly treats its initial value as
0before performing the XOR operation. - Type Coercion: If the operands are strings that do not represent valid integers, Bash attempts to evaluate them as variable names. If they do not resolve to integers, they are coerced to
0.
Execution Example
To illustrate the internal binary evaluation, consider a variableval initialized to 5 and an expression evaluating to 3:
valis parsed as the integer5. Its 4-bit binary representation is0101.- The right-hand operand is parsed as the integer
3. Its 4-bit binary representation is0011. - The bitwise XOR is applied: