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?: operator in Bash is a ternary conditional operator evaluated exclusively within arithmetic expansion contexts ($((...)), ((...)), or let). It evaluates a mathematical or logical expression and returns one of two specified integer values based on whether the condition resolves to non-zero (true) or zero (false).
Arithmetic Ternary Operator
Syntax:- Context Requirement: The operator is syntactically invalid in standard shell command execution; it must be enclosed in an arithmetic evaluation block.
- Condition Resolution: The
conditionis evaluated as an integer. In Bash arithmetic, any non-zero value represents logicaltrue, while0represents logicalfalse. - Short-Circuit Evaluation: The operator exhibits short-circuiting behavior. If
conditionis non-zero, onlyexpression_if_trueis evaluated. Ifconditionis zero, onlyexpression_if_falseis evaluated. Side effects (such as variable assignments) in the unselected branch will not occur. - Return Value: The integer result of the evaluated expression becomes the return value of the entire ternary operation.
Disambiguation: Parameter Expansion (:?)
While ?: is the arithmetic ternary operator, Bash also features a structurally similar parameter expansion operator, :? (colon-question mark), used for variable state validation rather than arithmetic logic.
Syntax:
- State Check: The shell evaluates whether
parameteris unset or null (an empty string). - Execution Flow:
- If
parameteris set and not null, the expansion yields the value ofparameter. - If
parameteris unset or null, the expansion evaluateswordand writes the resulting string to standard error (stderr). Ifwordis omitted, a default system error message is printed.
- If
- Termination: If the
:?expansion triggers the error condition within a non-interactive shell (such as a script), the shell immediately aborts execution and exits with a non-zero status.
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