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!= operator in Kotlin evaluates structural inequality. It determines whether two object references contain different underlying data (values), abstracting away the complexity of manual null-checking and method invocation.
Compiler Desugaring and Null Safety
Unlike Java, where!= on objects evaluates memory addresses, Kotlin’s != operator is translated by the compiler into a negated, null-safe call to the equals() function.
When you write a != b, the Kotlin compiler desugars it to the following expression:
- Safe Call (
?.): The compiler first checks if the left operand (a) isnull. - Non-Null Left Operand: If
ais notnull, it invokesa.equals(b). - Null Left Operand: If
aisnull, the safe call returnsnull, triggering the Elvis operator (?:). The expression then evaluatesb === null(referential equality) to check if the right operand is alsonull. - Logical Negation (
!): The final boolean result of the equality check is inverted.
Customizing Behavior
Because!= is tied to structural equality, you cannot overload the != operator directly using an operator fun. Instead, its behavior is dictated by the implementation of the equals(other: Any?): Boolean function inherited from Any.
To define custom structural inequality for a class, you must override equals():
Contrast with Referential Inequality (!==)
It is critical to distinguish the structural inequality operator (!=) from the referential inequality operator (!==).
!=evaluates state/value differences via theequals()contract.!==evaluates memory address differences, returningtrueonly if the two references point to completely different objects in the heap, regardless of their internal state.
Primitive Optimization
When the!= operator is used on Kotlin’s basic types (such as Int, Double, Boolean) that are not nullable, the compiler optimizes the operation. Instead of boxing the primitives and invoking equals(), it compiles directly down to the JVM’s native bytecode instructions for primitive comparison (e.g., if_icmpne), ensuring zero allocation overhead.
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