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# C Bitwise OR Assignment

The `|=` operator is the bitwise inclusive OR assignment operator in C. It performs a bitwise OR operation between the binary representations of the left and right operands, and subsequently assigns the computed result to the left operand.

## Syntax and Equivalence

```c theme={"dark"}
lvalue |= rvalue;
```

This compound assignment is semantically equivalent to the following expanded form, with the critical distinction that the `lvalue` is evaluated exactly once:

```c theme={"dark"}
lvalue = lvalue | (rvalue);
```

The single evaluation is significant when the left operand contains side effects, such as a post-increment operation (e.g., `*ptr++ |= 0x0F;`).

## Mechanics

The operator evaluates the operands bit by bit. For each corresponding bit position:

* If either or both bits are `1`, the resulting bit is `1`.
* If both bits are `0`, the resulting bit is `0`.

```c theme={"dark"}
#include <stdint.h>

int main(void) {
    uint8_t a = 10;  // Binary: 0000 1010
    uint8_t b = 6;   // Binary: 0000 0110

    a |= b;          // 'a' becomes 14
                     // Binary result: 0000 1110
                     
    return 0;
}
```

## Type Constraints

* **Integral Types Only:** Both operands must be of integral types (e.g., `char`, `short`, `int`, `long`, `unsigned` variants, or `_Bool`).
* **Floating-Point Prohibition:** Attempting to use `|=` with floating-point types (`float`, `double`) violates C language constraints and will trigger a compilation error.
* **Integer Promotions:** Before the bitwise operation occurs, standard integer promotions are applied to the operands. If the operands have different types, standard arithmetic conversions are performed to bring them to a common type before the OR operation and subsequent assignment.

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